Power savings for intersective polynomial differences and prime arguments. For every fixed intersective integer polynomial h of degree k ≥ 2 with positive leading coefficient, proves that a subset of $\{1,\ldots,N\}$ avoiding nonzero values $h(1),h(2),\ldots$ as differences has size $O_h(N^{1-c_k})$, with $c_k\gt 0$ depending only on degree. Here intersective means having a root modulo every modulus. For prime arguments, a power saving also holds when h has a unit root modulo every modulus, with exponent allowed to depend on h.
released 2026-10-05 | 1 theorem · 20 lemmas · 31 proofs · 19,740 words |
PLAY LEVEL 1 »(pdf)
An integer polynomial is intersective if it has a root modulo every positive integer. For each degree k ≥ 2, we prove that there is an exponent $c_k\gt 0$ such that every set $A\subseteq\{1,\ldots,N\}$ whose differences avoid all nonzero values $h(1),h(2),\ldots$, where h is an intersective polynomial of degree k with positive leading coefficient, satisfies $|A|=O_h(N^{1-c_k})$. The implied constant may depend on h, but the power-saving exponent depends only on its degree.
released 2026-10-05 | 2 theorems · 12 lemmas · 22 proofs · 17,704 words |
PLAY LEVEL 2 »(pdf)
Let h be a fixed integer polynomial of degree at least two with positive leading coefficient, having a unit root modulo every positive integer. We prove that any set $A\subseteq\{1,\ldots,N\}$ whose differences avoid all nonzero values $h(p)$ at primes satisfies $|A|\le C_hN^{1-c_h}$, where $c_h\gt 0$ and $C_h\ge1$ depend only on h. Thus the local unit-root condition gives a fixed power saving even when polynomial arguments are restricted to primes. The proof uses the companion zero-free half-plane theorem for Dirichlet L-functions to obtain the required prime-distribution estimates.
released 2026-09-24 | 2 theorems · 13 lemmas · 21 proofs · 18,536 words |
PLAY LEVEL 3 »(pdf)
We prove that there are absolute constants c > 0 and C < ∞ such that every set $A\subseteq\{1,\ldots,N\}$ with no nonzero square difference satisfies $|A|\le C N^{1-c}$. This answers the fixed-power question posed by Green and Sawhney.